0=1.1v+006v^2-200

Solution for 0=1.1v+006v^2-200 equation:

0=1.1v+006v^2-200

We move all terms to the left:

0-(1.1v+006v^2-200)=0

We add all the numbers together, and all the variables

-(1.1v+006v^2-200)=0

We get rid of parentheses

-006v^2-1.1v+200=0

We add all the numbers together, and all the variables

-6v^2-1.1v+200=0

a = -6; b = -1.1; c = +200;
Δ = b2-4ac
Δ = -1.12-4·(-6)·200
Δ = 4801.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.1)-\sqrt{4801.21}}{2*-6}=\frac{1.1-\sqrt{4801.21}}{-12}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.1)+\sqrt{4801.21}}{2*-6}=\frac{1.1+\sqrt{4801.21}}{-12}
$